A girl, starting from rest, travels a distance of 50m in 10s. Caculate her velocity at the end of 10s

Question

A girl, starting from rest, travels a distance of 50m in 10s. Caculate her velocity at the end of 10s

Answer 1

This is a two step process using kinematic equations.

The first part requires us to determine the acceleration. We are given distance and time and we also know the initial velocity was zero.

We use x=x0+v0t+0.5gt^2

This simplifies to 50 meters = 0.5 x acc x 10^2

This gives us acc = 1 m/s2

We now use another kinematic equation of v=v0+at (initial velocity is zero)

v= (1 m/s2)(10 s) = 10 m/s