l(l - 11) = 476
l2 - 11l - 476 = 0
(l - 28)(l + 17) = 0
l - 28 = 0
l = 28
28 - 11 = 17
28m x 17m
Bianca L.
asked 03/05/19Find the dimensions of a rectangle whose width is 11 meters less than its length, and whose area is 476 square meters.
l(l - 11) = 476
l2 - 11l - 476 = 0
(l - 28)(l + 17) = 0
l - 28 = 0
l = 28
28 - 11 = 17
28m x 17m
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