
Syed F. answered 09/30/19
Stuyvesant & U. of Michigan Alum with 4+ Yrs. of Corporate Experience
1 Liter of A = 8/15*X+3/15*Y+4/15*Z
1 liter of B = 4/15 * X + 3/15*Y + 8/15*Z
Cost of 1 liter of A = 8/15*$300 + 3/15*$240 + 4/15 *$180 = $256 / Liter
Cost of 1 liter of B = 4/15*$300 + 3/15*$240 + 8/15*$180 = $224 / Liter
Cost of 1 liter of C = $252,000/$1,000 = $252
Cost of 1 liter of C = $256*A/(A+B) + $224*B/(A+B)
$252 = $256*A/(A+B) + $224*B/(A+B)
252A + 252B = 256*A + 224*B
28 B = 4 A
7 B = A
The ratio of A to B in Chemical C is 7 to 1.