Algebra Problem

Question

A purse contains $5.35 in quarters and nickels. It contains five less than twice as many nickels as quarters. How many of each type of coin is in the purse?

Answer 1

Greetings! Lets solve this shall we ?

So, we must figure out how many nickles and quarter there are in the purse. Let x = Quarters and y = Nickels. Then, we must configure two equations such that

x = 2y - 5

0.25x + 0.05y = $5.35.............We use substitution such that

0.25(2y - 5) + 0.05y = $5.35

.5y - 1.25 + 0.05y = $5.35

0.55y - 1.25 = 5.35...........Add 1.25 to both sides such that

0.55y = 6.60..........Then divide 0.55 such that

y = 12 Nickels

Then plug 12 into the equation such that

x = 2(12) - 5

x = 19 Quarters

I hope this helped!