How would you solve -3x^2+5x+4y-8=0 and 2x+y-2=0 using Elimination or Substitution

Answer 1

2x+y-2=0

y=-2x+2

-3x^2+5x+4y-8=0

-3x^2+5x+4(-2x+2)-8=0

-3x^2+5x-8x+8-8=0

-3x^2-3x=0

x^2+x=0

x(x+1)=0

x=0 or x+1=0

x=0 or x=-1

y=4

(0,4) and (0,-1) are solutions