Dayaan M. answered 05/03/26
Trigonometry Tutor with a Bachelor's in Computer Science, 5.0 Rated
In order to find the other five trigonometric functions when you are given only cosecant and the quadrant, you can solve it entirely using a triangle.
If you recall, there is a mnemonic called SOH CAH TOA which helps you remember how to find the missing sides in a right triangle. What it means is:
sin(x) = opposite / hypotenuse
cos(x) = adjacent / hypotenuse
tan(x) = opposite / adjacent
From these, the reciprocal functions come from flipping the ratios. Since sine is opposite over hypotenuse, cosecant is its reciprocal, so:
csc(x) = hypotenuse / opposite
Lets understand this by doing an example:
Given:
csc(x) = 13/5 and x is in Quadrant II
Step 1:
Since csc(x) = hypotenuse / opposite:
hypotenuse = 13
opposite = 5
Step 2:
We can find the adjacent side by using the Pythagorean theorem:
a2 + b2 = c2
a and b can be opposite or adjacent but c is always hypotenuse so lets make a the opposite side so we can solve for b which would represent the adjacent side:
52 + b2 = 132
25 + b2 = 169
b2 = 169 - 25
b2 = 144
b = 12
So, adjacent = 12
Step 3:
In Quadrant II, sine is positive, but cosine and tangent are negative (as well as their reciprocals).
Step 4:
Now we can find all the other trigonometric functions:
sin(x) = opposite / hypotenuse = 5/13
cos(x) = adjacent / hypotenuse = -12/13
tan(x) = opposite / adjacent = -5/12
csc(x) = 13/5 (Given)
sec(x) = hypotenuse / adjacent = -13/12
cot(x) = adjacent / opposite = -12/5
So using SOH CAH TOA, you can interpret cosecant as hypotenuse over opposite, build a triangle, find the missing side, and then use the trig ratios to get all the other trigonometric functions.