
Whiz S. answered 10/29/18
Experienced and patient Math tutor
house rent for house 1 = x
house rent for house 2 = y
house rent for house 3 = z
y = x+300
z =y
amount received from house 1 = 12x
amount received from house 2 = 12y = 12(x+300)
amount received from house 3 = 10 z = 10 y =10(x+300)
12x + 12(x+300) + 10(x+300) =37200
12x+ 12x +3600 +10x +3000 = 37200
34x +6600 = 37200
34x = 30600
x = 900
y = 900 +300=1200
z=1200
house rent for house 1 = x= $900
house rent for house 2 = y=$1200
house rent for house 3 = z= $1200