Raymond B. answered 01/09/21
Math, microeconomics or criminal justice
A=kC
B=jC
A+B= kC +jC = (k+j)C k+j is a constant, so A+B = mC where m=k+j
A-B = kC-jC = (k-j)C k-j is a constant, so A-B = nC where n=k-j
sqrAB = sqrAsqrB = sqrkCsqrjC = sqrkjC
square both ends
sqrAB^2 = sqrkjC^2
AB = kjC kj is a constant,
AB =pC where p =kj, a constant