Ishwar S. answered 09/28/18
Tutor
5
(7)
University Professor - General and Organic Chemistry
Hello Deepak
React benzyl alcohol with molecular iodine and nitric acid to form a mixture of 2-iodobenzyl alcohol and 4-iodobenzyl alcohol products. I have written the basic reaction below, but am unable to draw the structures since there is no chem drawing tool available on this site.
Ph-CH2-OH + 1/2 I2 + HNO3 → 2-iodobenzyl alcohol + 4-iodobenzyl alcohol
2-Iodobenzyl alcohol and 4-iodobenzyl alcohol will have different solubilities in organic solvents, which allows you separate them from each other.
The -CH2OH group on the benzene ring is an activating group that directs electrophiles (iodine atom) ONLY to the ortho (2nd carbon) and para (4th carbon) positions of the benzene ring. As a result, 3-iodobenzyl alcohol CANNOT be prepared from the above reaction.