
Nietu P. answered 11/05/14
Tutor
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I bet your kid is going to love math.
Since given that tan A =2/3 then for the right angled triangle, side opposite to angle A is 2 and adjacent side is 3 and the diagonal will be √13.
So for this right angled triangle sin A = 2/√13 & cos A = 3 /√13
By Half-Angle Identities we know formula for tan (x/2) = sin (x) / [1+cos (x) ]
But for this problem we take angle as A instead of x. So, tan (A/2) = sin (A)/ [1+cos (A) ]
tan (A/2) = (2/√13) / [1+(3/√13) ]
= [2 / (3+√13) ] (3-√13) /(3-√13)
= [2 (3-√13) ] / 9-13
= 2 [(3-√13) ] / - 4
= (3-√13) / - 2
tan (A/2) = -(3-√13) / 2 or (√13 - 3) / 2