Ishwar S. answered 08/20/18
Tutor
5
(7)
University Professor - General and Organic Chemistry
Hello Tj
%-Error = ((accepted value - experimental value) / accepted value) x 100%
Note! In the above equation, the absolute value of the numerator must be used in the event you get a negative # as is the case in this problem.
%-Error = (Ι (7.13 - 9.95) l / 7.13) x 100%
= | -2.82 | / 7.13 x 100% = 39.6%