David S.

asked • 08/05/18

If the random variable X is normally distributed with a mean of 70 and a standard deviation of 10, find the following values of the distribution of X

find the first quartile 

1 Expert Answer

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Andy C. answered • 08/05/18

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Prob( X<=k) = 0.25
 
Prob ( z <= k)  where z = (X-70)/10
 
z=-0.675
 
X = -0.675*10 + 70 
 
    = -6.75 + 70
 
    = 63.25
 
 
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David S.

Thank you very much, sadly our tutor had to cut the class short due to an event. 
 
Can you please elaborate 
 
Prob( X<=k) = 0.25

Prob ( z <= k) where z = (X-70)/10

z=-0.675
 
Thank you 
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08/05/18

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