Rational Equations

Question

The water temperature in the ocean varies inversely with the depth of the water. The deeper a person dives, the colder the water becomes. At a depth of 1,100 meters, the water temperature is 3º Celsius. What is the water temperature at a depth of 900 meters?

Find the constant of proportionality k.
k =_______________

 

Using the k from above find the water temperature in degrees Celsius at a depth of 900 meters.
The water temperature will be__________ º Celsius.

Answer 1

Water Temp=K(1/Depth)

3Deg=K(1/1100Meters)

1100∗3DegMeters=k

k=3300DegMeters

Water Temp=3300DegMeters(1/900Meters)

Water Temp=(3300/900)Deg

Water Temp=3.67Deg