An integer from 100 through 999, inclusive, is chosen at random, what is the probability that the number chosen will have 0 as at least 1 digit.

Question

A: 19/900

B: 81/900

C: 90/900

D: 171/900

E: 271/1000

Answer 1

9*19/900 = 171/900  It is not in its most reduced form but D is the correct answer.

Answer 2

100 - 1 number

101 to 199 - 18 numbers

total 100 to 199 - 19 numbers.

200 to 299 - 19 numbers.

similarly ...

100 to 999 - 9*19 numbers

probability = 9*19/total=9*19/900=19/100.  D is equal to that.