word problems

Question

find two consecutive odd numbers such that 6 times the smaller added to 4 times the greater comes 138 

Answer 1

Any odd number: n

Next consecutive odd number: n+2

Six times the smaller: 6n

Four times the greater: 4(n+2) = 4n+8

 

Putting everything together,

6n + 4n + 8 = 138

10n = 130

n= 130/10 = 13

 

n+2 = 13+2 = 15