Find the equation of locus of a point P,the square of whose distance from the origin is 4 times it's y-co ordinate

Question

It's about to find the eqaequat with respect to both X and y axis

Answer 1

d² = 4y

x² + y² = 4y

x² + y² - 4y = 0

x² + y² - 4y + 4 = 4

x² + (y - 2)² = 2²

this is a circle centered at (0, 2) with a radius of 2.

 

Some solutions:

(2, 2), (-2, 2), (0, 0), and (0, 4)