f(g(x)) = 1/(√(x + 3) - 2
What's underneath the radical has to be positive, so...
x + 3 > 0
x > -3
The denominator can't equal 0.
√(x + 3) - 2 ≠ 0
√(x + 3) ≠ 2
x + 3 ≠ 4
x ≠ 1
So, the domain is x > -3, x ≠ 1
Sammi J.
asked 06/07/18
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.