Arturo O. answered • 05/18/18

Experienced Physics Teacher for Physics Tutoring

^{-1}(1/2) = 180° - 30° = 150°

Nesen E.

asked • 05/18/18Help me with this please, I can't find a way

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Arturo O. answered • 05/18/18

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Experienced Physics Teacher for Physics Tutoring

There is more than one way to solve this. You can find the small angle from trigonometry, and then subtract it from 180° to get the large angle. (This will be clear if you draw a picture.)

Note that the sine of the small angle is 1/2. Then

Large angle = 180° - sin^{-1}(1/2) = 180° - 30° = 150°

Alexander B. answered • 05/18/18

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PhD in Engineering with 20 yrs of Math and Science Teaching Experience

The answer is: 90^{o} + arccos(1/2) = 150^{o}

Alexander B.

tutor

Hi Nesen,

It would help understanding the formula if you draw the picture of the Rombus. Result could be obtained using either the arccos() function as shown in my solution, or by using arcsin() function as suggested by Arturo O. The resulting number will stay the same.

Best regards,

Alexander

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05/18/18

Nesen E.

Thank you very much, I understood it!

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05/18/18

Alexander B.

tutor

You are welcome! Best of luck!

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05/18/18

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Nesen E.

05/18/18