
Terry V. answered 05/10/18
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Just take some guesses at the b and h. Area is 1/2 times b times h, so check the product of b *h by trial and error (How's that for being "mathy"?)
1,27= 27
2, 26= 52
3, 25= 75
4, 24
5, 23
6, 22 =132
7, 21
8, 20
9, 19
10, 18 = 180
1,27= 27
2, 26= 52
3, 25= 75
4, 24
5, 23
6, 22 =132
7, 21
8, 20
9, 19
10, 18 = 180
11, 17 = 187
12, 16 = 192
13, 15 = 195
14, 14 = 196
14, 14 = 196
I actually didn't have to check so many. I see the pattern. Therefore, I know that the dimensions 14 and 14 will give the largest area. It doesn't matter which is the height and which is the base.
Without using calculus, here's another method which uses the graph and properties of a parabola which will face downward.
b + h = 28
b = 28 - h
We must find where the maximum "is" of the function that can be graphed as a parabola.
Area = 1/2 * b * h = 1/2 *(h(28-h))
b = 28 - h
We must find where the maximum "is" of the function that can be graphed as a parabola.
Area = 1/2 * b * h = 1/2 *(h(28-h))
The 1/2 can be ignored when finding zeros (setting function = 0) and find the zeros of h(28-h).
It faces down and the zeros are at h=28 and h=0. The maximum which is at the vertex is found half way between the zeros at (28+0)/2 = 14 =h = b ---same answer.
It faces down and the zeros are at h=28 and h=0. The maximum which is at the vertex is found half way between the zeros at (28+0)/2 = 14 =h = b ---same answer.