
Arturo O. answered 05/07/18
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You need to find the unit tangent vector T(t), and evaluate the dot product of T(t) with your acceleration vector a(t). That will give the tangential acceleration at(t) at time t. I assume you started out with a position vector vector r(t), then you found a velocity vector
v(t) = dr(t)/dt,
and then an acceleration vector
a(t) = dv(t)/dt
If you already have dr(t)/dt, the unit tangent vector is just
T(t) = dr(t)/dt / |dr(t)/dt| = v(t) / |v(t)|
Then
at(t) = T(t) · a(t) = [v(t) / |v(t)|] · a(t)

Arturo O.
Yes, since you want the projection of a in the direction of the unit vector T.
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05/08/18
Ashley H.
05/08/18