
Bobosharif S. answered 04/30/18
Tutor
4.4
(32)
Advanced User of Windows
3x + 6y + 5 = 0 (divide by 3)
2x + 4y - 7 = 0 (divide by 2)
x+2y+5/3=0
x+2y-7/2=0
These two lines are parallel. The distance between two parallel lines
ax+by+c1 and ax+by+c2=0 is calculated as
d=|c2-c1|/√(a2+b2)=
=|5/3+7/2|/√(1+4)=31/(6√5).
Chola R.
05/01/18