Investment question

Question

$5900 is invested, part of it at 12% and part of it at 9%. For a certain year, the total yield is $624.00. How much was invested at each rate?

Answer 1

Split the amount invested ($5900) into two parts,  x   and   5900-x

 

Then multiply each amount by the interest rate. The sum must equal $624.

 

So your equation is

 

9%x + 12%(5900-x) = 624

 

.09x + .12(5900-x) = 624

 

can you solve for x from here?