Finding zeros of a polynomial

Question

The problem is 6x^3+25x^2-x-20.  Gave all the possible rational zeros, then did synthetic division -4] 6 25 -x -20 and got 6x^2+x-5 and that is where I got stuck.  I am needing help going from there.  I know there are going to be 3 zeros and one of them is -4.  I need to know if so far I am doing this right and then where to go from here. 

Answer 1

6x³+25x²-x-20=(x+1)(x+4)(6x-5).

So the zeros are x=-4, x=-1, x=5/6

Answer 2

Next step is to factor 6x²+x-5. You can do this by splitting the middle term (+x) and then factoring by grouping. Solving this will give you the other two zeroes.