Jannet C.
asked • 09/14/14
sin 2x 4 + cos2 x dx
Phillip R.
answered • 09/14/14
Top Notch Math and Science Tutoring from Brown Univ Grad
∫ sin2x / (4 + cos2x) dx
let u = 4 +cos2x
du = -2sin2x dx
-(1/2)du = sin2x dx
∫ du / u = ln ι u ι + C = ln (4 + cos2x) + c
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Jannet C.
09/14/14