Arturo O. answered 03/22/18
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If it loses half of its speed for each 0.25 m of penetration, then its speed obeys the law
v(x) = v0 (1 - 0.5)x/0.25 = v0 (0.5)x/0.25
v0 = speed at which it strikes the target
x = penetration depth in meters
Set v(x) = 0 and solve for x. However, theoretically, it never reaches a speed of zero, although it quickly converges toward zero. To solve a problem like this realistically, you need to specify a tiny maximum speed close to zero, and solve for the distance to attain that tiny speed.