2KClO3 —> 2KCl + 3O2

Question

How many grams of KClO3 are required to produce 62 moles of KCl?

Answer 1

According to the balanced equatio, KCl and KClO3 are present in a 2:2 ratio. So for 62 moles of KCl produced that means 62 moles of KClO3 were required:

 

62 moles KCl x (2 moles KClO3/2 moles KCl) = 62 moles KClO3

 

from there, we just multiply moles of KCLO3 by its molar mass in order to convert it to grams:

 

62 moles KClO3 x (122.55g/1 mole) = 7598.1 g KClO3  

Or 7600 g when rounded to sig figs