Andrew M. answered • 02/01/18
Tutor
New to Wyzant
Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors
x = number large dogs
x + 36 = number small dogs
x + (x + 36) = 49
2x + 36 = 49
2x = 13
x = 6.5 large dogs
x + 36 = 42.5 small dogs
Since I highly doubt we have any "half dogs" the numbers given in the problem are off.
If there were an even number of total dogs this would work. As it is, we have either
6 large, 43 small or 7 large, 42 small ...
Neither case actually gives 36 more small dogs and a total of 49.
Kelsea V.
If there were only 13 large dogs then rather than there being 36 more smaller dogs, there would be 23 more. Therefore, you're answer is invalid. Good try though!
Report
02/01/18
Michael O.
First of all, you are using the word (then) improperly. "Then" represents an element of "Time".
"Than" is used when making a comparison. Just saying...
Now as far as the Math question is concerned, God forbid that this is what is expected from any child or adult for that matter coming from our teaching institutions.
It's total designed for failure.
Shame on you teacher! :-$
Report
02/09/18
Pradeep R.
"There is 36 more small dogs (s) than large dogs (l)." --> s - l = 36 -- (1) "There are 49 dogs entered in the dog show." ----> s + l = 49 ----(2) Solve for s (no. of small dogs) = 42.5 (technically not correct)
Report
08/16/19
Jam S.
Does the problem not just tell you the number of small dogs? I do not understand the complication. If you have 49 total things and 36 of those things are smaller and we need to know how many of the things are smaller is it not simply the 36 smaller things? OMG that was a mouthful. 49-36=13. So 36 small things this the remaining are the large things. I wish someone could explain why in the first equation he says that x+small dogs =small dogs.
Report
02/29/20
Sam M.
02/01/18