Arturo O. answered 01/20/18
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The question is incomplete, but I assume you want to find when the rock strikes the ground.
h(t) = -4.9t2 + 28t + 39 [t in sec, h in meters]
It strikes the ground when h(t) = 0.
Set h(t) = 0 and solve the resulting quadratic equation for t. You will get a positive and a negative solution. Since time starts at the moment of throwing the rock (t = 0), discard the negative solution.