g(x)=10^x+2

k(x)=ln(x+3)

f(x)=log(x−1)

h(x)=e^x+2

Which function’s inverse has the greatest value at x=4?

g(x)=10^x+2

k(x)=ln(x+3)

f(x)=log(x−1)

h(x)=e^x+2

g(x)=10^x+2

k(x)=ln(x+3)

f(x)=log(x−1)

h(x)=e^x+2

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Function G(x)

------------------------

4 = 10^x + 2

2 = 10^x

log 2 = log 10^x

1og 2 = x log 10

x = log 2/ log 10 = 0.30103

Function K(x)

----------------

4 = ln(x+3)

e^4 = x+3

e^4 - 3 = x = 54.59815

Function F(x)

------------------

4 = log(x-1)

e^4 = x-1

e^4 + 1 = x <--- this will be LARGER than the previous

so it's the largest thus far

----------------------------------------------------------

Function H(x)

4 = e^x + 2

2 = e^x

ln 2 = x = 0.693147

Winner:

K(x) = ln(x+3)

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