Find the inverse of the function

Question

What is the inverse of the function f(x)=(sqrt(x−5)/8)−2?

f−1(x)=64(x−2)^2−5
f−1(x)=8(x+2)^2+5
f−1(x)=64(x+2)^2+5
f−1(x)=8(x−2)^2+5

Answer 1

y=√(x−5)/8−2.

(y+2)²=(x-5)/8

8(y+2)²+5=x

So, inverse function is

 

f^-1(x)=8(x+2)²+5