
John M. answered 01/13/18
Tutor
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Engineering manager professional, proficient in all levels of Math
- Set up the equations
- 2b + 1c = 800 {Eqn 1}
- 1b + 2c = 700 {Eqn 2}
- You have two unknowns (b and c) and two equations, so you can get a unique answer to the problem.
- There are a couple of ways to do this. I'll use the method of substitution:
- In Eqn 1, solve for c. So, c = 800 - 2b {Eqn 3}
- Now substitute this value of c into Eqn 2. So, 1b + 2* (800-2b) = 700
- Solve for b.
- b +1600 -4b =700.
- -3b = -900 --> b = 300
- To find c, substitute this value of b back into eqn 3. c= 800- 2(300) --> c = 200
- Check the answer, b = 300 and c = 200 by substituting these values into eqn 2. Does 1b + 2c = 700?
- 1(300) + 2(200) = 700?
- 300 + 400 = 700
- The check works.