Francisco E. answered 08/12/14
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Francisco; Civil Engineering, Math., Science, Spanish, Computers.
When he is going to the west he will be against the wind and then his real speed will be (450-50) mph, when he is turning back, we have that the speed is (450+50)= 500 mph
The two equations are:
(450-50) t1=(450+50)t2
t1+t2=3
t2=3-t1
400t1=500(3-t1)
900t1=1500
t1= 1500/900 = (1(2/3)) hours, so he will go 400*5/3 = 666.67 miles
If we divide this distance by 500 miles we obtain (1(1/3)) hours which is t2