Philip P. answered • 07/31/14

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The table is asking you what value the functions (f(x), g(x), and h(x) take when x has a specific value. The variable y is used as a placeholder for f(x), g(x), or h(x). For example:

f(x) = y = 3x

^{2}- 3When

**x = 0**, just replace the x in f(x) with a zero:**y =**f(x=0) = 3*(0)

^{2 }- 3 =

**-3**

So in the table under x=0, enter -3 for y.

When x = 1, y = f(x=1) = 3*(1)

^{2}- 3 = 3 - 3 = 0When x = 2, y = f(x=2) = 3*(2)

^{2}- 3 = 3*4 - 3 = 12 - 3 = 9So for f(x), the table looks like:

x= | 0 | 1 | 2 | 3 |

y= | -3 | 0 | 9 | ? |

Can you complete the rest?

April B.

01/13/17