If N is a three digits number and last two digits of squre of N are 54 (n^2 = ...54), then how many values of n are possible? ?

Question

If N is a three digits number and last two digits of squre of N are 54 (n^2 = ...54), then how many values of n are possible? ?

 

a. 2

b. 20

c. 0

d. 1

Answer 1

2² = 4, nothing to carry to make the 5

8² = 64, too much to carry to make the 5

 

C.