Pass through (7,4) and has slope of -8/3

Question

Plss help me in my homework

Answer 1

Hi Kirk,

I'm not sure what the question is, but I can show you a couple of ways to write equations of a line.



Here you can use the point-slope equation:

y - y1 = m(x-x1)

You have a point, (7,4), where x1 = 7 and y1 = 4, and a slope, -8/3

Plug 7 into x1, 4 into y1, and -8/3 into m:

Here is a correct equation: y-4 = -8/3(x-7)

You can also solve for y to put it into the form: y=mx +b

y-4 = -8/3(x-7)
y = -8/3x + 56/3 +4

This is the slope-intercept form:y = -8/3x +68/3

 

Now you have a y-intercept of 68/3 and a slope of -8/3

I hope this helps! Feel free to message me.