
Arturo O. answered 11/07/17
Tutor
5.0
(66)
Experienced Physics Teacher for Physics Tutoring
After 1 hour, you are left with (100 - 29)% = 71%
y(t) = 325 (0.71)t
y(1.5) = 325 (0.71)1.5 = 194.4
After 1.5 hours, only 194.4 milligrams remain.
100 = 325 (0.71)T
log(100/325) = T log(0.71)
T = log(100/325) / log(0.71) = 3.44 hours
It takes 3.44 hours for the initial amount to drop to 100 milligrams.