
Arturo O. answered 11/05/17
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The electron starts with energy
En = -13.60 eV / n2
To remove it from the H atom means to increase its energy to zero by absorbing a photon of energy hc/λ.
hc/λ = -En = 13.60 eV / n2
n2 = (λ / hc)(13.6 eV)
n2 = {(1460 x 10-9 m) / [(4.136 x 10-15 eV·s)(3.00 x 108 m/s)]} (13.60 eV)
n2 ≅ 16.003 ≅ 16 [To get an integer you need really precise values of the constants.]
n = 4