Victoria P.

asked • 11/05/17

Baby snakes' genotype at two additional genes for which the mother snake was heterozygous and found that two of the babies were heterozygous.

In 2006, a 19-year-old female Colomian rainbow boa, Epicrates maurus, who had been raised alone since she was born, gave birth to a litter of 11 parthenogenetic offspring. Seven of the baby snakes were healthy, two were deformed and were euthanized, and two were stillborn. The genotype of the living baby snakes was determined at four genes for which the mother snake was heterozygous. Each baby was found to be homozygous at all four genes, but the babies were homozygous for different alleles. At each gene, some babies were homozygous for one of their mother's alleles, while other babies were homozygous for the other of their mother's alleles.
 
Would I have to change whatever answer I got if I had to clearly explain how the normal events of meiosis may have been modified to produce the parthenogenetic babies in the female Colombian rainbow boa? 

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