A bacteria culture starts with 3000 bacteria. After 3 hours the estimated count is 48000. Whatbis the doubling periond?

Question

It is a possible test question

Answer 1

T = doubling period in hours

t = hours

 

A(t) = A₀ (2)^t/T

 

For t = 3 hours,

 

48000 = 3000 (2)^3/T

 

 

48000/3000 = 2^3/T

 

16 = 2^3/T

 

log16 = (3/T)log2

 

log16 / log2 = 3/T

 

T = 3 / (log16 / log2) hours = 0.75 hours

 

Test is the answer:

 

Is 

 

48000 = 3000 (2)^3/0.75 ?