J.R. S. answered 11/03/17
Tutor
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Ph.D. in Biochemistry--University Professor--Chemistry Tutor
For these problems, it is best to work in step/stages. Each temperature change, and each phase change should be done separately. So, in this problem you have a 150 g mass (this will be the same for all calculations), and you are taking it from solid ice at -14ºC to 30ºC. This will require 3 separate steps:
(1) taking solid ice from -14º to 0º
(2) melting the ice at 0º (a phase change). Remember that phase changes do NOT have a ∆T associated with them)
(3) taking the liquid water from 0ºC to 30ºC
Now, for the calculations using q = mC∆T and/or q = m∆H
(1) q = mC∆T
q = (150 g)(2.09 J/g/deg)(14 deg) = 4389 J (2.09 is the value I have for Cice)
(2) q = m∆Hfus
q = (150 g)(334 J/g) = 50,100 J
(3) q = mC∆T
q = (150 g)(4.184 J/g/deg)(30 deg)
q = 18,828 J
Then just add up all of the joules and convert to kJ if needed.
Total heat = 73,317 J = 73.3 kJ