Csc(theta)tan(theta)

Question

If cos(theta)=7/9 and theta is in quadrant 4 then what is csc(theta)tan(theta)

Answer 1

a² + b² = c²

7² + b² = 9²

49 + b² = 81

b² = 32

b = √32 = 4√2    b is the length of the side opposite theta.

cscθ = 9/4√2

tanθ = 4√2/7