
Arturo O. answered 10/28/17
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Here is something that will help you solve these problems:
i1 = i
i2 = -1
i3 = -i
i4 = 1
To find in, look at whether n is a multiple of 4, or has a remainder of 1, 2, or 3.
n = 4k + 1 ⇒ in = i
n = 4k + 2 ⇒ in = -1
n = 4k + 3 ⇒ in = -i
n = 4k ⇒ in = 1
i24 = i4(6) = 1
i-26 = 1/i26 = 1/i4(6)+2 = 1/-1 = -1
⇒
i24 + i-26 = 1 - 1 = 0