J.R. S. answered • 10/24/17

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Calculate mass of lead:

1.00 cm

^{3}lead x 11.4 g/cm^{3}= 11.4 g lead on one side of balanceTo balance that, one needs 11.4 g of iron on the other pan. Calculate volume of iron to give you 11.4 g:

11.4 g iron x 1 cm

^{3}/7.87 g =**1.45 cm**^{3}of iron needed
Brenda V.

similarly what would be the answer to this question. What volume of iron (density 7.87 g/cm3) would be required to balance a 3.95 cm3 sample of lead (density 11.4 g/cm3) on a two-pan laboratory balance?09/06/21