Distance = (Rate)(Time)
If each train travels from A to B, the distances traveled are the same.
Let r1 = rate of first train and r2 = rate of second train.
Then, (r1)(1) = (r2)(1.5). So, r2 = (2/3)r1
Let T = time elapsed (since 4 PM) when the trains meet
Then, r1T + (2/3)r1T = total distance from A to B = D
But, D = (r1)(1) = r1.
So, r1T + (2/3)r1T = r1
(5/3)r1T = r1
Therefore, T = 3/5 hours.
The trains meet at 4:36 PM.