Can you help me with this AP Chemistry Stoichiometry problem?

Question

What volume of sulfur dioxide can be produced by the complete reaction of 3.82g of calcium sulfite with excess HCl (aq) wheb the final SO2 pressure is 8.27 torr at 44°C

Answer 1

CaSO₃ + 2HCl ==> SO₂(g) + CaCl₂ + H₂O

moles CaSO₃ used = 3.82 g x 1 mole/120 g = 0.0318 moles

moles SO₂ produced = 0.0318 moles CaSO₃ x 1 moles SO₂/mole CaSO₃ = 0.0318 moles SO₂

From PV = nRT and solving for V, you have V = nRT/P

V = (0.0318 moles)(62.4 L-torr/K-mole)(317K)/8.27 torr

V = 76.1 liters