Find four consecutive odd integers such that 4 times the sum of the first three is equal to 30 more than 6 times the largest.

Question

Algebra word problems

Answer 1

Let x = the smallest odd integer

Let x + 2 = the next consecutive odd integer

Let x + 4 = the following consecutive odd integer

Let x + 6 = the largest odd integer

4(x + x + 2 + x + 4) = 6(x + 6) + 30

4(3x + 6) = 6x + 36 + 30

12x + 24 = 6x + 66

6x = 42

x = 7

x + 2 = 9

x + 4 = 11

 x + 6 = 13