A mixture weighing 155 kg contains three substances A, B and C in the ratio ½ : 1/5 : 1/3. Find the quantity of each substance in the mixture.

Question

Please explain HOW to get the answer

Answer 1

Take your proportion and multiply each part by 30 to get easier ratio 15:6:10. 

 

This can be thought of as having 31 parts (15+6+10)

so 155 divided by 31 is 5; each part (of the 31 parts) is 5 kg.

 

A: 15 times 5 = 75 kg

B: 6 times 5 = 30 kg

C: 10 times 5 = 50 kg.

 

These three qantities add up to 155 kg.