
David W. answered 09/23/17
Tutor
4.7
(90)
Experienced Prof
The number of karats is TMI. The percentages of pure gold are important.
The question is, “How many grams of 75% gold must be mixed with 50% gold to make 100 grams of 58% gold?”
There are 100 grams of 58% gold; how many grams of pure gold is that? 58 grams.
Now, you have a standard mixture problem.
x = grams of 75% gold; solve for x
mixed with (100-x) grams of 50% gold
Now, the number of grams of pure gold in x grams of 75% gold is 0.75x.
The number of grams of pure gold in (100-x) grams of 50% gold is 0.50(100-x).
The question is, “How many grams of 75% gold must be mixed with 50% gold to make 100 grams of 58% gold?”
There are 100 grams of 58% gold; how many grams of pure gold is that? 58 grams.
Now, you have a standard mixture problem.
x = grams of 75% gold; solve for x
mixed with (100-x) grams of 50% gold
Now, the number of grams of pure gold in x grams of 75% gold is 0.75x.
The number of grams of pure gold in (100-x) grams of 50% gold is 0.50(100-x).
Together, there is a total of 58 grams of pure gold (in a mixture weighing 100 grams).
0.75x + 0.50(100-x) = 58
75x + 50(100-x) = 5800 [multiply by 100]
75x + 5000 - 50x = 5800
25x = 800
x = 32 grams
Check:
Does a mixture of 32 grams of a 75% gold (24 karat) with 68 grams of 50% gold (12 karat) make 100 grams of 58% gold (14 karat)?
x = 32 grams
Check:
Does a mixture of 32 grams of a 75% gold (24 karat) with 68 grams of 50% gold (12 karat) make 100 grams of 58% gold (14 karat)?
Does 32 + 68 = 100? yes
Does 32*0.75 + 68*0.50 = 100*0.58 ?
24 + 34 = 58 ?
58 = 58 ? yes
Carolyn M.
09/22/17