Alan M.

asked • 09/09/17

A food type question where cross multiplying wont help!?

Here's a food type question but its kinda tricky.
 
Alan is making food for himself and decides to go shopping for something to eat, he finds a product that reads 1 cup and 1/3 cup is 300 calories. He also reads that the serving size is 3 on the box. Alan will only eat one serving a day and on the 3rd day alan will have no more of the product. Alan would like to stretch out the duration of product so that he can keep keep eating it for 6 days, and decides to only use a 3/4 cup for measuring to stretch the duration of the product, if alan does this will he be able to finish the product on the 6th day?
 
----
 
Here's where i am confused. 
 
1 and 1/3 cup into decimal =  1.3 / that is 3 servings
and he is trying to make the product last for 6 days
so 3/4 cup into decimal is 0.75 so i set it up like this..
 
1.3          0.75
-----  =  ------
3             6
 
and i got 1.73...umm..what...what am i doing wrong?

1 Expert Answer

By:

Arturo O. answered • 09/09/17

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Experienced Physics Teacher for Physics Tutoring

Alan M.

Arturo the calories portion of the problem is part of another question, sorry, I just need help with this one.
 
1 and 1/3 cups is one serving.
Entire product is 3 servings.
 
He wants to stretch the product out so that so that it will last 6 days, and thus cuts down 1 and 1/3 cups to 3/4 cups.
The question is will that be enough.
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09/09/17

Arturo O.

OK.  The entire box has 3(1 + 1/3) cups = 3(4/3) cups = 4 cups.  He wants 4 cups to last for 6 days, so each day he should eat no more than 4/6 = 2/3 of a cup.  This is the same as half of (1 + 1/3) cups = (1/2)(4/3) cups = 2/3 cups.
 
3/4 cups > 2/3 cups.  He will be consuming too much each day, and it will not last.
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09/09/17

Alan M.

THANK YOU SO MUCH Arturo!,
 
I was wondering why cross multiplying was giving me weird numbers, but the approach you showed me makes more sense then the what I was doing. I was lost doing cross mutinying! Thanks again!
 
 
 
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09/09/17

Arturo O.

You are welcome, Alan.
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09/09/17

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