
Lynn S.
asked 08/21/17how many baseballs will fit in a container 301.5 x 96.99 x 105.04
These are regulation size baseballs
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1 Expert Answer

Arturo O. answered 08/21/17
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This same question keeps coming up.
You have length L, width W, and height H of a container (specify units, please). You did not state the diameter of the balls, with units. Suppose the diameter is D.
Compute L/D, and round down to the next lower integer if L/D is not an integer. That gives you how many balls fit side by side along the length of the box. Do the same for W/D and H/D, rounding down to an integer where needed. Then the maximum number of balls that fit in the box, side by side along the length and width, and stacked vertically, is
(L/D)(W/D)(H/D) = LWH / D3,
with integer rounding as noted above.
Kleiner L.
I am still confused what the numbers are 11 33 and 10 so i get 54 as the number but the end of the equation is LWH divided by 9 to the third?
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08/23/17

Arturo O.
You need to MULTIPLY the 3 numbers, not add them. Remember you are stacking rows and columns of balls in a 3-dimensional array.
Assuming 9 is the correct diameter,
L/D = 301.5/9 = 33.5 [Round down to 33]
W/D = 96.99/9 ≅ 10.8 [round down to 10]
H/D = 105.04/9 ≅ 11.7 [round down to 11]
Your values of 33, 10, and 11 are correct. Now multiply these 3 rounded results and get
(L/D)(W/D)(H/D) = (33)(10)(11) = 3630
You can fit 3630 balls of diameter 9 in a container of the dimensions given in the problem statement, with the balls placed side by side along the length and width, and stacked vertically.
By the way.
(L/D)(W/D)(H/D) = LWH / D3,
But it is better to first round off each factor, and then multiply.
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08/23/17
BASSIM A.
how can you calculate the reverse.. size of a square box to fit 20 x 2cm balls
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10/25/18
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Mark M.
08/21/17